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n^2+201n-11352=0
a = 1; b = 201; c = -11352;
Δ = b2-4ac
Δ = 2012-4·1·(-11352)
Δ = 85809
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(201)-\sqrt{85809}}{2*1}=\frac{-201-\sqrt{85809}}{2} $$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(201)+\sqrt{85809}}{2*1}=\frac{-201+\sqrt{85809}}{2} $
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